Homework+Postings

Post your homework answers on this page. Put your solutions in number order below the correct date.

 * __10/28/09 -- pg. 176__**

18) not continuous jeremy


 * __10/27/09 -- pgs.169&176__**

5)//Decreases//@ (-inf.,-2)(2,+inf.) .. //Increases// @ (-2,2) -HUEY

11) f'(1)=0 marsha

12) f(x)=x^2-5x+4, [1,4] answer- 5/2

7. undefined -Bevi :)
 * __10/26/09 -- pg.169__**

9. 2, absolute max. (relative max.) -Elisabeth 11. 1, absolute maximum(and relative maximum) 2, absolute minimum(and relative maximum) 3, absolute maximum(and relative minimum)

$==W!ll Peterson==$

14. f(x) = x²(x²-4) f '(x) = 4x³-8x --> 4x(x²-2) x=0 -Michael

19. f ( x ) = 2 ( 3 - x ) max → ( -1, 8 ) min → ( 2, 2 )

-Summer-

20. I hope i did this right >.< max 5 when x=5 min 5/3 when x=0 - Word

48. (-x(y+1/-x+1)-x+(y+1/-x+1)+y+2)/(-x+1)^2 -Marsha
 * __10/14/09 -- pg. 147__**


 * __10/13/09 -- pg. 146__**

12) (sin((pi)x + cos((pi)y)^2 = 2

answer: cos((pi)x))/(sin((pi)y)

13) sinx = x(1 + tany)

answer = (cosx - tany - 1) / (xsec²y)

$==W!ll Peterson==$

**24. (x+y)³ = x³+y³ @ (-1,1) answer: dy/dx = (3(x+y)²-3x²)/(3y²-3(x+y)²), (-1,1) = -1 -Matt

25. x^(2/3) + y^(2/3) = 5 2/3x^(-1/3) + 2/3y^(-1/3)(dy/dx) = 0 Simplified: dy/dx = -6 ³root(y)/6 ³root(x) at (8,1) answer: -1/2 i think.. -Michael

26) ~Huey

**10/12/09 -- pg. 146 1. x^2+y^2=36 answer: dy/dx= -x/y -Bevi

5, x^3-xy+y^2=4 answer: (y-3x^2)(2y-x) -Elisabeth

6.x²y+y²x=-2 answer: dy/dx=(-x²-2xy)/(x²+2xy) -Brianna 

7.X³Y³-Y=X Answer: dy/dx=(1-3X²Y³)/(3X³Y²-1) -Kash  10/6/09 -- pg. 137

8. 30x(4-x^2) -word

10) 18/5(9t+2)^3/5 -summer

72. y-4=2/3(x-1) marsha

__9/28/09 -- pg. 126 and 128__

- Ben (Direct link: http://img38.imageshack.us/img38/9258/eqn7245.png)
 * 40)

42) f(x) = (sinx)/x --> ((x)(cosx)-(sinx)(1))/x² f '(x) = (xcosx-sinx)/x² -Michael

97) f(x)=3sin(x) answer = -3sin(x) -dilan**

__9/24/09 -- pg. 126__

__2t² - 14t -4__ k ( 2t - 7 )²
 * 8) -Summer-

11)

17) f(x) = x cosx f ' (╥/4) = root2/8(4-╥) $==W!ll Peterson==$

18) f(x)=sinx/x (x)(cosx)-(sinx)(1)/(x)^2 xcosx-sinx/(x)^2 I dont know what to do after this, please help if you can-Elisabeth**

[**Well eliZabeth, I think that I may be wrong, but this is what I got... ((x)(cosx)-(sinx)(1))/(x^2) (xcosx-sinx)/(x^2) Now I plugged in (╥/6) for "x." ((╥/6)((root3)/2)) - (1/2) Next, I multiply together the first term and I will convert the one half to (6/12) to make simplifying easier. (((root3)╥)/12) - (6/12) Finally, since these have the same denometers I make it into one fraction. f'(x)= ((root3)╥ - 6)/12 Once again, I may be totally wrong. ~Huey**]

__9/23/09 -- pg. 126__ =2x^3 -2x^2 +2x -2 +2x^3 -4x^2 =4x^3 -6x^2 +2x -2 =2(2x^3 -3x^2 +x -1) -Will
 * 1) g'(x)=(x^2 +1)(2x-2) + (x^2 -2x)(2x)

2) f '(x)= 24x^3 + 15x^2 - 12 ~Tiffany** __9/21/09 -- pg. 115__ Sorry, it is (0,2) and NOT (0,0). Thanks Kash. -Huey
 * 57)

59) y=1/x^2 answer- no horizontal tagents -dilan novosad**

__9/16/09 -- pg. 115__

answer=pie-sint -Elisabeth
 * 20) g(t)=pi cost

23) answer = (1/x^2) - 3cos(x) ~ Ben

37) answer = 3 Summer Barre

54) y=x^3+x answer: y+2=4(x+1) ~Marsha**

__9/15/09 -- pg. 115__ answer: 0 Bevi Wilson
 * 3)

18) f(x) = 2x^3 - x^2 + 3x answer = 6x^2 - 1 $==W!ll Peterson==$

41) g(t)=t^2-(4/t^3) answer = 2t + (12/t^4) -novosad

47) **

__9/14/09 -- pg. 104__

m= 2x slope at (2,1) = 4
 * 8)

9) tl;dr slope at (0,0) = 3 ~ Ben (I'll explain how to do this later) Fixed it!.Or not. I'll do it differently from now on I guess. Slightly.

10) slope=2t slope at (-2, 7) = -4
 * will d**

__9/9/09 -- pg. 88__

none -Elisabeth
 * 14) f(x)= -4x/x²+4

16) (2x-3)/(x^2-25) VA x=5 x=-5 

22) f(x) = (4x^2+4x-24)/(x^4-2x^3-9x^2+18x) VA x=0 and x=3 $==W!ll Peterson==$

24) h(x)=(x^2-4)/(x^3+2x^2+x+2) none -dilan

35) lim __x²__ [ goes to positive infinity ] x→3+ x² - 9 *summer*

36) lim x->4- x^2/x^2+16 goes to positive infinity <3 Word**

__9/8/09 -- pg. 79__

f(x) = x^2-2x+1 all ya gotta do is look at it and its obviously continuous at all real x values, as it is a normal function. <3 word
 * 33)

37) f(x) = (x) / (x^2-x) = (x) / (x(x-1)) <--Factor out x from the denominator. discontinuous at x=1 (nonremovable) and x=0 (removable).
 * The x's in the numerator and denominator cancel, thus the function is

38)

39) f(x) = (x)/(x²+1) continuous for all values of x -Michael

41) f(x) = (x+2) / (x²-3x-10) non-removable at x = 5, removable at x = -2 -Matt

58) g(x)={ 4sin(x)/(x), x<0} { a-2x, x≥0} a=4 -dilan

83) f(x)=x^2 + x - 1< [0,5], f(c) = 11 f(3) = 11 $==W!ll Peterson==$**

9/1/09 -- pg.79 4) a)2 b)2 c)2 not continuous,sepearted at x=-2 ---dana

8) lim __2-x 2-x__ x→2+ x²-4 (x+2)(x-2) cancel Answer: 1/4 -**Michael

17) lim f(x), where f(x) = x --> 1 {x^3 + 1, x < 1 {x + 1, x > 1** Answer = 2 $==W!ll Peterson==$

19) lim cotx x→pi -1/0 //Answer: limit does not exist - Elisabeth//

__8/31/09 -- pg. 68__ A = delta... 2(x+Ax)-2x/Ax = 2x+2Ax-2x/Ax = 2Ax/Ax = [2] lim Ax -> 0** Word
 * 59)

A = delta ((x+Ax)^2 - x^2)/Ax = 2x lim Ax -> 0 --Ryan
 * 60)

67) lim sinX / 5X ▲X → 0** Answer: 1/5 -Brett

Huey
 * As x --> ZERO!

lim (1-cosh)² h→0 h answer: 0** Bevi
 * 73

__8/28/09-- pg. 68__


 * 54 = (Root 2) / 4

Kash


 * 1) 56 = 1/4

$==W!ll Peterson==$**

__8/27/09-- pg. 67__**

x->1
 * 1) 12 lim (3x^3 - 2x^2 + 4)>(3-2+4) = 5

Lim 2x-3 x→3 x+5 answer: 3/8
 * 16

x→3 answer = -2
 * 1) 18 lim ²root(x+1)/(x-4)

x→4 ³ root(8) = 2
 * 1) 20 lim ³ root(x+4)

lim (2x-1)^3 x→0 answer: -1
 * 22

X→pi answer: -1 (sry couldn't find a pi sign)
 * 1) 32 lim cos3X